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Two moving-coil galvanometer, P and Q, a...

Two moving-coil galvanometer, P and Q, are alike in all respects except that P's coil has 10 turns of resistance `2Omega` and Q's coil has 100 turns of resistance `30 Omega`. Compare their (i) current sensitivities (ii) Voltage sensitivities.

Text Solution

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Data: `N_(p) = 10, G_(p)= 2Omega, N_(Q) = 100, G_(Q) = 30 Omega`
(i) The current sensitivity, `S_(1) = (NAB)/C`
`therefore S_(LP)/S_(LQ) = N_(P)/N_(Q) = 10/100=1/10`
(ii) The voltage sensitivity, `S_(v) = S_(l)/G`
`therefore S_(V.P)/S_(I.Q).G_(Q)/G_(P)=1/(10.30/2)=1.5`
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