Calculate the value of the of resistance needed to convert a moving-coil galvanometer of `60 Omega` which gives a full scale deflection for a current of 50 mA into a voltmeter of range `0-50`V.

Explanation

Data: `G=60Omega, I_(g)= 50 mA = 5 xx 10^(-2) A, I=5A`
V=50 V
`R_(s) = V/I_(g)-G=50/(5 xx 10^(-2)) - 60=1000-60 = 940 Omega`
A resistance of `940 Omega` should be connected in series with the coil of galvanometer to measure voltage up to 50 V.