Home
Class 12
PHYSICS
In a cyclotron, a magnetic filed of 3.5 ...

In a cyclotron, a magnetic filed of `3.5 Wb//m^(2)` is used to accelerate protons. What should be the time interval in which the electric field between the dees should be reversed? [Mass of the proton `=1.67 xx 10^(-27) kg`, charge on the proton `=1.6 xx 10^(-19)`C]

Text Solution

Verified by Experts

Data: `B=3.5 Wb//m^(2), m=1.67 xx 10^(-27) kg, q=1.6 xx 10^(-19)` C,
`T= (2pim)/(qB)`
`therefore t=T/2 = (pim)/(qB) = (3.142 xx 1.67 xx 10^(-27))/(3.5 xx 1.6 xx 10^(-19)) = 9.37 xx 10^(-9) s`
This is the required time interval.
Promotional Banner

Topper's Solved these Questions

  • SOLVED PROBLEMS-II

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Magnetism|12 Videos

  • SOLVED PROBLEMS-II

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Electromagnetic Induction|13 Videos

  • SOLVED PROBLEMS-II

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Current Electricity|11 Videos

  • SOLVED PROBLEMS - I

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise ASSIGNMENTS|24 Videos

  • VERY SHORT ANSWER QUESTIONS

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise COMMUNICATION SYSTEMS|11 Videos

Similar Questions

Explore conceptually related problems

In a cyclotron, a magnetic field of 2*4T is used to accelerate protons. How rapidly should the electric field between the dees be reversed? The mass and the charge of protons are 1*67xx10^(-27)kg and 1*6xx10^(-19)C respectively.

In cyclotron, magnetic field of 1.4 Wb//m^(2) is used. To accelerate protons, how rapidly should the electric field between the Dees be reversed? (pi=3.142, Mp = 1.67xx10^(-27) kg, 3=1.6xx10^(-19)C)

Protons are accelerated in a cyclotron using a magnetic field of 1.3 T. Calculate the frequency with which the electric field between the dees should be reversed.

Find the rest mass energy of a proton in MeV. [m_(p) = 1.673 xx 10^(-27) kg]

In a cycloton, the protons are to be accelerated with a magnitude field of magnitude 1*5T . How rapidly should the electric field between the dees be reversed? Mass and charge of proton are 1*67xx10^(-27)kg and 1*6xx10^(-19)C respectively.

A cyclotron in which flux density is 1.4 T is employed to accelerate protons. How rapidly should the field between the dees be reversed if mass of protoon be taken as 1.6 xx 10^(-27) kg ?

The maximum kinetic energy of protons in a cyclotron of radius 0.4 m in a magnetic field of 0.5 T is (mass of proton = 1.67 xx 10^(-27) kg, charge of proton = 1.6 xx 10^(-19) C)

A beam of protons moving with a velocity of 4 xx 10^(5) m/s enetrs a uniform magnetic field of 0.3 T at an angle of 60◦ with the magnetic field. What is the radius of the helical path described by the proton beam? [m_p=1.67 xx 10^(-27) kg and the charge on the proton =1.6 xx 10^(-19) C]

A beam of protons with a velocity 4 xx 10^(5) m/sec enters a uniform magnetic field of 0.3 Testa at an angle of 60^(@) to the magnetic field. Find the radius of the helical path taken by the proton beam. Also find the pitch of the helix, which is the distance travelled by a proton in the beam parallel to the magnetic field during one period of rotation [Mass of proton = 1.67 xx 10^(-27) kg. charge on proton = 1.6 xx 10^(19)C ]

A proton is moving perpendicular to a uniform magnetic field of 2.5 tesla with 2 MeV kinetic energy. The force on proton is _______N. (Mass of proton= 1.6 xx 10^(-27) kg, charge of proton =1.6 xx 10^(-19) C)