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The photoelectric work function of a met...

The photoelectric work function of a metal is ` 5.5`eV . Calculate the maximum speed of the fastest photoelectrons emitted when radiation of photon energy `5.8` eV is incident on the metal surface.

Text Solution

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Data : `phi = 5.5 eV, hv = 5.8 eV, e = 1.6 xx 10^(-19) C, m_(e ) = 9.1 xx 10^(-31) kg`
` 1/2 m_(e)v_("max")^(2) = hv - phi`
` = 5.8 - 5.5 = 0.3 `eV
` = 0.3 xx 1.6 xx 10^(-19)`
` = 4.8 xx 10^(-20)J`
` :. v_("max") = sqrt((2(4.8 xx 10^(-20)))/(9.1 xx 10^(-31)))`
` = sqrt(96/(9.1) xx 10^(10))`
` = 3.248 xx 10^(5) m//s`
`{:(log 96,," "1.9823),(log 9.1,,ul(-0.9590)),(,," "1.0233),(,,ul(" "xx1/2)),(,,ul(" "0.5116)):}`
AL ` 0.5116 = 3.248`
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