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A battery of emf 3 V and internal resist...

A battery of emf 3 V and internal resistance `1 Omega` is connected in parallel with a cell of emf 1.5 V and internal resistance `0.5 Omega` with their like poles together. The combination is used to pass a current through a resistor of resistance of `5 Omega`. Using Kirchhoffs circuital laws, find the current through the `5 Omega` resistor.

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Verified by Experts

The correct Answer is:
`3//8A`
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