How is the energy of activation determined ?

Explanation

For the given reaction, rate constants `k_(1) a nd k_(2)` are measured at two different temperatures `T_(1)` and `T_(2)` respectively. Then
`log_(10).(k_(2))/(k_(1))=E_(a)(T_(2)-T_(1))/(2.303RxxT_(1)xxT_(2))`
where `E_(a)` is the energy of activation.
Hence by substituting appropriate values, energy of activation `E_(a)` for the reaction is determined.