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Predict the sign of DeltaS in the follow...

Predict the sign of `DeltaS` in the following processes. Give reasons for your answer :
(a) `N_(2)O_(4(g))to 2NO_(2(g))`
(b)`Fe_(2)O_(3(s)) + 3H_(2(g)) to 2Fe_((s)) +3H_(2)O_((g))`

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`N_(2)O_(4(g))to 2NO_(2(g))`
Since 1 mole `N_(2)O_(4)` on dissociation gives two moles of `NO_(2)` , the number of molecules increase, disorder increases hence entropy increases,`DeltaS gt 0`.
`Fe_(2)O_(3(s)) + 3H_(2(g)) to 2Fe_((s)) +3H_(2)O_((g))`
In the reaction number of moles of gaseous reactants and products are same, hence `DeltaS = 0`.
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