Describe the acton of aqueous KOH (or NaOH) on isopropyl bromide

Explanation

To describe the action of aqueous KOH (or NaOH) on isopropyl bromide, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is isopropyl bromide, which has the structure \( \text{C}_3\text{H}_7\text{Br} \) or \( \text{(CH}_3)_2\text{CHOBr} \) (isopropyl group attached to bromine).
- The reagent is aqueous KOH (or NaOH), providing hydroxide ions (\( \text{OH}^- \)).

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