Describe the action of hydroiodic acid on ethyl methyl ether .

Explanation

To describe the action of hydroiodic acid (HI) on ethyl methyl ether (C2H5OCH3), we can break down the reaction into several steps:

### Step 1: Protonation of the Ether
When ethyl methyl ether is treated with hydroiodic acid, the ether oxygen atom, which has a lone pair of electrons, will first protonate. This means that the ether oxygen will attract a hydrogen ion (H+) from HI, forming an oxonium ion.

**Reaction:**
\[ \text{C}_2\text{H}_5\text{OCH}_3 + \text{H}^+ \rightarrow \text{C}_2\text{H}_5\text{OH}^+ \text{CH}_3 \]

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