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Boiling point of a solvent is 80.2^(@)C....

Boiling point of a solvent is `80.2^(@)C`. When 0.419g of the solute of molar mass 252.4 g mol- is dissolved im 75 g of the above solvent, the boiling point of the solution is found to be `80.256^(@)C`. Find the molal elevation constant.

Text Solution

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The correct Answer is:
`K_(b)=2.53Kg"mol"^(-1)`
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