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The minimum number of meiotic divisions ...

The minimum number of meiotic divisions required to produce 120 viable seeds in pea plant is …….. .

A

150

B

60

C

120

D

90

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The correct Answer is:
To determine the minimum number of meiotic divisions required to produce 120 viable seeds in a pea plant, we can break down the problem into steps. ### Step-by-Step Solution: 1. **Understanding Gamete Production**: - In pea plants, male gametes are produced from microspores through meiosis. Each microspore undergoes meiosis to produce 4 male gametes. - Female gametes are produced from megaspores. Each megaspore undergoes meiosis to produce 1 female gamete. 2. **Calculating Male Gametes**: - To produce 120 male gametes, we need to determine how many microspores are required. Since each microspore produces 4 male gametes: \[ \text{Number of microspores needed} = \frac{120 \text{ male gametes}}{4 \text{ male gametes per microspore}} = 30 \text{ microspores} \] - Each microspore undergoes 1 meiotic division to produce 4 male gametes. Therefore, the number of meiotic divisions required for male gametes is: \[ \text{Meiotic divisions for male gametes} = 30 \text{ microspores} = 30 \text{ meiotic divisions} \] 3. **Calculating Female Gametes**: - To produce 120 female gametes, we need to determine how many megaspores are required. Since each megaspore produces 1 female gamete: \[ \text{Number of megaspores needed} = 120 \text{ female gametes} = 120 \text{ megaspores} \] - Each megaspore undergoes 1 meiotic division to produce 1 female gamete. Therefore, the number of meiotic divisions required for female gametes is: \[ \text{Meiotic divisions for female gametes} = 120 \text{ megaspores} = 120 \text{ meiotic divisions} \] 4. **Total Meiotic Divisions**: - Now, we add the meiotic divisions required for both male and female gametes: \[ \text{Total meiotic divisions} = \text{Meiotic divisions for male gametes} + \text{Meiotic divisions for female gametes} \] \[ \text{Total meiotic divisions} = 30 + 120 = 150 \] ### Conclusion: The minimum number of meiotic divisions required to produce 120 viable seeds in a pea plant is **150**.
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NAVNEET PUBLICATION - MAHARASHTRA BOARD-MULTIPLE CHOICE QUESTIONS -Reproduction in Plants
  1. The secondary nucleus is formed by the fusion of ………… .

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  2. To produce 500 pollen grains, how many microspore mother cells are req...

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  3. The minimum number of meiotic divisions required to produce 120 viable...

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  4. How many meiotic divisions are required for the formation of 100 seeds...

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  5. For the formation of 50 seeds, how many minimum meiotic divisions are ...

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  6. In bisexual flowers, maturation of gynoecium before androecium is know...

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  7. Considering the mode of asexual reproduction, match the Column I with ...

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  8. In angiosperms during development of embryo, the suspensor cell develo...

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  9. If there are 1280 microspores in a tetralocular anther. How many micro...

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  10. A versatile anther is an adaptation for ……….. Type of pollination.

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  11. If the number of chromosomes in as endosperm cell is 27, what will be ...

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  12. Anemophilous pollination is mainly observed in

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  13. Vegetative propagation takes place with the help of leaves in ……….. Pl...

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  14. Endosperm of angiosperm is

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  15. A group of three cells situated at the base of the embryo sac are call...

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  16. The female gametophyte in angiosperms is a ……….. Nucleated structure.

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  17. When more than 2 male gametes are produced in a pollen tube, it is cal...

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  18. ………. Is formed in angiosperms by triple fusion.

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  19. Embryo sac is

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  20. During double fertilization second male gamete fuses with ……… .

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