A normal couple gives the birth to one haemophilic son and a normal daughter. Work out the cross to show the genotypes of parents and progeny.

Explanation

(1) Since one son is haemophilic, his mother must be carrier.
(2) Therefore, genotype of mother is `X^(h)`. Father is normal, hence his genotype will be XY.
(3)
(4) From the cross, it is clear that one daughter and one son is normal while one son is haemophilic and one daughter is carrier.