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cal//g, cal//g.^(@)C,kcal//kg.^(@)C, erg...

`cal//g, cal//g.^(@)C,kcal//kg.^(@)C, `erg `//`g`.^(@)C`.

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Cal/g. (It is a unit of specific latent heat. Others are units of specific heat capacity ).
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Three liquids A, B and C of specific heats 1cal//g-^@C, 0.5 cal//g-^@C and 0.25cal//g-^@C are at temperatures 20^@C, 40^@C and 60^@C respectively. Find temperature in equilibrium if they are mixed together. Their masses are equal.

The final temperature, when 10 g of steam at 100^@ C is passed into an ice block of mass 100 g (L_(steam) = 540 cal//g, L_(ice) = 80 cal//g , S_(water) =1 cal//g^(@) C) is

A copper calorimeter of mass 100g and temperature 30^(@)C contains water of mass 200 g and temperature 30^(@)C . If a pieceof ice of mass 40g and temperature 0^(@)C is added to it,what will be the maximum temperature of the mixture ? [c( copper ) = 0.1 cal // g.^(@)C, c ( water ) = 1 cal //g.^(@) C , L = 80 cal //g ]

6 gm of steam at 100^@ C is mixed with 6 gm of ice at 0^@ C . Find the mass of steam left uncondensed. (L_(f)=80 cal//g,L_(v)= 540cal//g, S_(water) = 1cal//g-^(@) C) .

5 g of steam at 100^(@)C is mixed with 10 g of ice at 0^(@)C . Choose correct alternative /s) :- (Given s_("water") = 1"cal"//g ^(@)C, L_(F) = 80 cal//g , L_(V) = 540cal//g )

0 g ice at 0^@C is converted into steam at 100^@C . Find total heat required . (L_f = 80 cal//g, S_w = 1cal//g-^@C, l_v = 540 cal//g)

How much heat is required to convert 8.0 g of ice at -15^@ to steam at 100^@ ? (Given, c_(ice) = 0.53 cal//g-^@C, L_f = 80 cal//g and L_v = 539 cal//g, and c_(water) = 1 cal//g-^@C) .

Find the amount of heat enegy required to convert 100 g of ice at -10^(@)C into stea at 120^(@)C . (Take S_(ice)=0.5" cal "g^(-1).^(@)C^(-1),S_(W)=1" cal "g^(-1)^(@)C^(-1),S_("Steam")=0.5" cal "g^(-1).^(@)C,L_(f)=80" cal "g^(-1),L_(V)=540" cal "g^(-1) )

1 gram of ice at -10^@ C is converted to steam at 100^@ C the amount of heat required is (S_(ice) = 0.5 cal//g -^(@) C) (L_(v) = 536 cal//g & L_(f) = 80 cal//g,) .