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The escape velocity on the moon is less ...

The escape velocity on the moon is less than that on the earth.

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The correct Answer is:
TRUE
Escape velocity of an object from the earth.
`v_(esc)(1)=sqrt((2GM_(1))/(R_(1)))`
Escape velocity of an object from the moon,
`v_(esc)(2)=sqrt((2GM_(2))/(R_(2)))`
`therefore (v_(esc)(2))/(v_(esc)(1))=sqrt((M_(2))/(M_(1))xx(R_(1))/(R_(2)))`
Now, `(M_(1) "(Earth)")/(M_(2) "(Moon)")=81 and (R_(1)"(Earth)")/(R_(2)"(Moon)")=3.7`
`therefore (v_(esc)(2))/(v_(esc)(2))=sqrt((3.7)/(81)) lt 1`
Thus, `v_(esc)(2) lt v_(esc)(1)`
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