Find the magnitude of the acceleration due to gravity at the surface of the earth. ( M ` = 6 xx 10^(24) ` Kg, R = 6400 Km)

Explanation

Data : ` M = 6 xx 10^(24) Kg,` = R= 6400 Kg = ` 6.4 xx 10^(6)` m .
` G = 6.67 xx 10^(-11) N.m^(2)//Kg^(2) , g = ? `
`= (66.7 xx 6)/((6.4)^(2)) m//s^(2) = 9.77 m//s^(2)`
The magnitude of the acceleration due to gravity at the surface of the earth = ` 9. 77 m//s^(2)`