A ball falls off a table and reaches the ground in 1 s. Assuming g = `10 m//s^(2) ` , calculate its speed on reaching the ground (2 marks) and the height of the table.

Explanation

` (i) s = ut + 1/2 gt^(2) = 1/2 gt^(2) " for " ` u = 0 m/s
` s = 1/2 xx 10 m// s^(2) xx (1s)^(2) = 5m `
The height of the table = 5 m
(ii) ` v = u + at = u + gt = 0 m//s + 10 m//s^(2) xx 1s = 10 ` m/s
The velocity of the ball on reaching the ground = 10 m/s .