In the above example (4) how much time will the satellite take to complete one revolution above 35780 km around the earth ?

Explanation

Given : R = 6400 km = ` 6.4 xx 10^(6) ` m, h = 35780 km = ` 3.5780 xx 10^(7)` m
` v_(c) = 3.08 km//s = 3.08 xx 10^(3) m//s, T = ? ` ?
The time required for the satellite to compelte one revolution around the earth .
` T = (2pi (R +h))/(v_(c)) = ( 2 xx 3.142 xx ( 6.4 xx 10^(6) + 35.78 xx 10^(6))m)/( 3.08 xx 10^(3) m //s) `
` = ( 6.284 xx 42.18 xx 10^(3))/( 3.08) ` s= Approx 86060 s
= 23 hours 54 min 20 seconds