What is escape velocity ?...

What is escape velocity ?

Text Solution

Verified by Experts

In general, when a body is thrown vertcally upward from the earth's surface, its velocity goes on decreasing and after some time the body falls back to the ground. If its initial velocity is increased, the maximum height attained by its is more. But it does fall back to the ground. If the initial velocity is increased continuosly. for a particular initial velocity. the body can overcome the earth's gravitational force and move to inifinity and come to rest there. The velocity is called teh escape velocity.

Topper's Solved these Questions

SHORT NOTES
NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Periodic Classification of Elements|1 Videos
SHORT NOTES
NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Chemical Reactions and Equations|3 Videos
SCIENTIFIC REASONS
NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Assignment|4 Videos
SKETCHING, EXPLANATION, CORRECTION OF DIAGRAMS
NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Observe the above figure and answer the questions below:|5 Videos

The escape velocity at the surface of Earth is approximately 8 km/s. What is the escape velocity for a planet whose radius is 4 times and whose mass is 100 times that of Earth?

1.6 km/s

8 km/s

40 km/s

200 km/s

The escape velocity of a body on the surface of the earth is V_(e) . What is the escape velocity on a planet whose radius is thrice the radius of the earth and whose mass is double the mass of the earth?

`sqrt((3)/(2))V_(e)`

`sqrt((2)/(3))Ve`

`(2)/(3)V_(e)`

`(sqrt(3))/(2)V_(e)`

What is the escape velocity for body on the surface of planet on which the accelearation due to gravity is (3.1)^(2)ms^(2) and whose radius is 8100 km ?

`2790 kms^(-1)`

`27.9 kms^(-1)`

`27.9 sqrt(5) kms^(-1)`

`2.79 sqrt(5) kms^(-1)`