Write the balanced equations for the following reactions :
`CH_(4)+O_(2)rarrCO_(2)+H_(2)O`

Explanation

Step 1 : Rewrite the given equation as it is
`CH_(4) + O_(2) to CO_(2) + H_(2)O`
Step 2 : Write the number of atoms of each element in the unbalanced equation on both sides of the equation .

Step 3 : To balance the number of oxygen atoms :

To equalise the number of oxygen atoms , we use 2 as the coefficient of `O_(2)` in the reactants and 2 as the coefficient of `H_(2)O` in the product .
Now , the partly balanced equation becomes
`CH_(4) + 2O_(2) to CO_(2) + 2H_(2)O`
Now , count the atoms of each element of both sides of the equation . The number of atoms on both sides are equal . Hence , the balanced equation is,
`CH_(4) + 2 O_(2) to CO_(2) + 2H_(2)O`
Now , indicate the physical states of the reactants and the products .
`CH_(4 (g)) + 2O_(2 (g)) to CO_(2 (g)) + 2H_(2)O _((l))`