`f(x)` and `g(x)` are two differentiable functions in `[0,2]` such that `f"(x)=g"(x)=0, f'(1)=2, g'(1)=4, f(2)=3, g(2)=9` then `f(x)-g(x)` at `x=3/2` is

f(x) and g(x) are two differentiable functions on [0, 2] such that f''(x)-g''(x)=0, f'(1)=2, g'(1)=4, f(2)=3 and g(2)=9 , then [f(x)-g(x)] at x=(3)/(2) is equal to -

If f(x) and g(x) are twice differentiable functions on (0,3) satisfying f"(x) = g"(x), f'(1) = 4, g'(1)=6,f(2)=3, g(2) = 9, then f(1)-g(1) is

f(x) and g(x) are two differentiable functions on [0,2], such that f^('')(x) - g^('') (x) = 0,f' (1) = 4,g'(1) = 2, f(2) = 9, g(2) = 3, then f(x) = g(x) at x = 3//2 is

f(x) and g(x) are two differentiable functions on [0,2] such that f^('')(x) - g^('')(x) = 0 , f^(')(1) = 4, g^(')(1) =2, f(2) = 9, g(2) =3 , then f(x) - g(x) at x = 3/2 is

Let f(x)and g(x) be twice differentiable functions on [0,2] satisfying f''(x)=g''(x) , f'(1)=4 , g'(1)=6 , f(2)=3 and g(2)=9 . Then what is f(x)-g(x) at x=4 equal to ?

If f(x) and g(x) are twice differentiable functions on (0, 3) satisfying f''(x)=g''(x), f'(1)=4,g'(1)=6,f(2)=3,g(2)=9," then "f(1)-g(1) is -

If f(x), g(x) be twice differentiable function on [0,2] satisfying f''(x)=g''(x) , f'(1)=4 and g'(1)=6, f(2)=3, g(2)=9, then f(x)-g(x) at x=4 equals to:- (a) -16 (b) -10 (c) -8