" (x) "(1)/((x-1)(x-2))+(1)/((x-2)(x-3))+(1)/((x-3)(x-4))=(1)/(6)

Long-answer type questions (L.A.) (1)/((x-1)(x-2))+(1)/((x-2)(x-3))+(1)/((x-3)(x-4))=(1)/(6)(xne1,2,3,4)

Solve the following quadratic equations by factorization: (1)/((x-1)(x-2))+(1)/((x-2)(x-3))+(1)/((x-3)(x-4))=(1)/(6)

Solve the following quadratic equations by factorization: 1/((x-1)(x-2))+1/((x-2)(x-3))+1/((x-3)(x-4))=1/6

Solve the following quadratic equation by the method of factorisation:(xxv) 1/((x-1)(x-2))+1/((x-2)(x-3))+1/((x-3)(x-4))=1/6(x!=1,2,3,4)

1/((x-2)(x-4))+1/((x-4)(x-6))+1/((x-6)(x-8))+1/3=0

Solve: 1/((x-1)(x-2))+1/((x-2)(x-3))+1/((x-3)(x-4))=1/6[x!=1,2,3,4]

Check whether the following are quadratic equations : (1) (x-1)^(2)=2(x-3) (2) x^(2)-2x=(-2)(3-x) (3) (x-2)(x+1)=(x-1)(x+3) (4) (x-3)(2x+1)=x(x+5) (5) (2x-1)(x-3)=(x+5)(x-1) (6) x^(2)+3x+1=(x-2)^(2) (7) (x+2)^(3)=2x(x^(2)-1) (8) x^(3)-4x^(2)-x+1=(x-2)^(3)

Add: (3x^(2) - (1)/(5)x + (7)/(3)) + ((-1)/(4)x^(2) + (1)/(3)x - (1)/(6)) + (-2x^(2) - (1)/(2)x + 5)