(1)/(x+1)+(2(x-2))/(1)+(1)/((x-2)(x-3))+(x-3)(x-4)=0

Check whether the following are quadratic equations : (1) (x-1)^(2)=2(x-3) (2) x^(2)-2x=(-2)(3-x) (3) (x-2)(x+1)=(x-1)(x+3) (4) (x-3)(2x+1)=x(x+5) (5) (2x-1)(x-3)=(x+5)(x-1) (6) x^(2)+3x+1=(x-2)^(2) (7) (x+2)^(3)=2x(x^(2)-1) (8) x^(3)-4x^(2)-x+1=(x-2)^(3)

Solve : (i)" "((x-1)\(x-2)(x-3))/((x+1)(x+2)(x+3))" "(ii) " "(x^(4)+x^(2)+1)/(x^(2)+4x-5)lt0

Solve : (i)" "((x-1)\(x-2)(x-3))/((x+1)(x+2)(x+3))" "(ii) " "(x^(4)+x^(2)+1)/(x^(2)+4x-5)lt0

If x+(1)/(x)=3, calcuate x^(2)+(1)/(x^(2)),x^(3)+(1)/(x^(3)) and x^(4)+(1)/(x^(4))

If x ne 0 and x + (1)/(x) = 2 , then show that: x^(2)+ (1)/(x^(2))= x^(3) + (1)/(x^(3)) = x^(4) + (1)/(x^(4))

Solve : ((x-1)^2(x-2)^3(x-4))/((x+1)(x+3)^4) ge0

Solve |((x+1),0,0)) , ((2x+1),(x-1),0)) , ((3x+1),(2x-1),(x-2))| =0