A cabe of iron (density`= 8000kg m^(-1)` specific beat capacity `= 470g J kg^(-1)K^(-1))` is heated to a high temperature and is placed on a larger block of ice at `0^(@)C` The cubemelts the ice below it displaces the water and sinks in the final equilibriumposition its upper surface just inside the ice calculate th initial temperature of the cube .Noglect any loss of head outside the ice and the cube .The density of ice `= 900 kg m^(-1)` and the latent head of fasion of ice `= 3.36 xx 10^(5)J kg^(-1)`

A cube of iron (density = 8000kg m^(-1) , specific heat capacity = 470g J kg^(-1)K^(-1) ) is heated to a high temperature and is placed on a larger block of ice at 0^(@)C . The cube melts the ice below it, displaces the water and sinks in the final equilibrium position its upper surface is just inside the ice. Calculate the initial temperature of the cube. Neglect any loss of heat outside the ice and the cube .The density of ice = 900 kg m^(-1) and the latent heat of fusion of ice = 3.36 xx 10^(5)J kg^(-1)

A piece of ice of mass 40 g is added to 200 g of water at 50^@ C. Calculate the final temperature of water when all the ice has melted. Specific heat capacity of water = 4200 J kg^(-1) K^(-1) and specific latent heat of fusion of ice = 336 xx 10^3" J "kg^(-1) .

Find the final temperature and composition of the mixtue of 1 kg of ice at 0^(@)C and 1.5 kg of water at 45^(@)C . Given that specific heat of water is 4200 J/kg and latent heat of fusion of ice is 3.36xx10^(5)J//kg

If 10 g of ice is added to 40 g of water at 15^(@)C , then the temperature of the mixture is (specific heat of water = 4.2 xx 10^(3) j kg^(-1) K^(-1) , Latent heat of fusion of ice = 3.36 xx 10^(5) j kg^(-1) )

If 10 g of ice is added to 40 g of water at 15^(@)C , then the temperature of the mixture is (specific heat of water = 4.2 xx 10^(3) j kg^(-1) K^(-1) , Latent heat of fusion of ice = 3.36 xx 10^(5) j kg^(-1) )

A piece of ice of mass of 100g and at temperature 0^(@)C is put in 200g of water of 25^(@) How much ice will melt as the temperature of the water reaches 0^(@)C ? The specific heat capacity of water = 4200 J kg ^(-1)K^(-1) and the latent heat of ice = 3.36 xx 10^(5)J kg^(-1)

A piece of ice of mass of 100g and at temperature 0^(@)C is put in 200g of water of 25^(@) How much ice will melt as the temperature of the water reaches 0^(@)C ? The specific heat capacity of water = 4200 J kg ^(-1)K^(-1) and the latent heat of ice = 3.36 xx 10^(5)J kg^(-1)

A piece of ice of mass of 100g and at temperature 0^(@)C is put in 200g of water of 25^(@) How much ice will melt as the temperature of the water reaches 0^(@)C ? The specific heat capacity of water = 4200 J kg ^(-1)K^(-1) and the latent heat of ice = 3.36 xx 10^(5)J kg^(-1)

Ice melts at the rate of 5 kg per hour in a cold storage when the temperature outside is 300 K. Calculate the minimum power of the motor is to be used to drive a refrigerator to just prevent the melting of ice. Specific latent heat of usion of ice =3.3 xx 10 ^(5) J kg ^(-1) .[E.Q]