The resistance of 0.1 N solution of a salt is found to be `2.5xx10^(3) Omega`. The equivalent conductance of the solution is (Cell constant `=1.15 cm^(-1)`)

The resistnce of 0.1 N solution of a salt is found to be 2.5xx10^(3) ohms. The equivalent conductance of the solution is ( cell constant =1.15cm^(-1) )

The resistance of 0.1 N solution of salt is found to be 2.5 xx 10^(3) Omega . The equivalent conductance of solution (cell constant = 1.15 cm^(-1) ) in Omega^(-1) cm^(2) eq^(-1) is

The resistance of decinormal solution is found to be 2.5 xx 10^(3) Omega . The equivalent conductance of the solution is (cell constant = 1.25 cm^(–1) )

The resistance of decinormal solution is found to be 2.5 xx 10^(3) Omega . The equivalent conductance of the solution is (cell constant = 1.25 cm^(–1) )

The resistance of a 0.5 N solution of salt is 20 Omega .Calculate the equivalent conductance of the solution if the platinum electrodes are 1.5 cm apart and each having an area of 3.0cm^(2) .

The resistance of a 1N solution of salt is 50 Omega . Calculate the equivalent conductance of the solution, if the two platinum electrodes in solution are 2.1 cm apart and each having an area of 4.2 cm^(2) .

The resistance of a 1N solution of salt is 50 Omega . Calculate the equivalent conductance of the solution, if the two platinum electrodes in solution are 2.1 cm apart and each having an area of 4.2 cm^(2) .