Determine the voltage drop across the resistor `R_(1)` in the circuit given below with `E=60 V, R_(1)=18 Omega, R_(2)=10 Omega`.

Determine the voltage drop across the resistor R_1 in the circuit given below with E = 65V, R_1 = 50Omega, R_2 = 100 Omega, R_3 = 100 Omega and R_4 300 Omega

Determine the voltage drop across the resistor R_1 in the circuit given below with E = 65V, R_1 = 50 OmegaR_2 = 100 Omega, R_3 = 100 Omega, and R_4 300 Omega.

Find the voltage drop across 18 Omega resistor in the given circuit.

If the voltage across 500 Omega is 5 V. then R_2 is

Three resistors of 10 Omega , 15 Omega and 20 Omega are connected in series in a circuit. If the potential drop across the 15 Omega resistor is 3 V, find the current in the circuit and potential drop across the 10 Omega resistor.

In the given cirucit, determine current through branch having indicated resistor R_(4) Given R_(1) = R_(2) = 4Omega, R_(3) = R_(4) = 2Omega R_(5) = 5Omega epsilon_(1) =5 V, epsilon _(2) =10V

In the circuit shown, the voltage drop across the 15Omega resistor is 30V having the polarity as indicated. The ratio of potential difference across 5Omega resistor and resistance R is :

In the given cirucit, determine current through branch having indicated resistor R_(4) Given R_(1) = R_(2) = 4Omega, R_(3) = R_(4) R_(5) = 2Omega epsilon_(1) =5 V, epsilon _(2) =10V

In the circuit shown in Fig. the emf of the sources is equal to xi = 5.0 V and the resistances are equal to R_(1) = 4.0 Omega and R_(2) = 6.0 Omega . The internal resistance of the source equals R = 1.10 Omega . Find the currents flowing through the resistances R_(1) and R_(2) .