If f: Q->Q ,\ \ g: Q->Q are two function...

If `f: Q->Q ,\ \ g: Q->Q` are two functions defined by `f(x)=2x` and `g(x)=x+2` , show that `f` and `g` are bijective maps. Verify that `(gof)^(-1)=f^(-1)\ og^(-1)` .

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