Home
Class 12
MATHS
A particle moves along the curve y=x^(3/...

A particle moves along the curve `y=x^(3/2)` in the first quadrant in such a way that its distance from the origin increases at the rate of `11` units per second. Then the value of `dx/dt` when `x=3` is given by

Promotional Banner

Similar Questions

Explore conceptually related problems

A particle moves along the curve y=x^((3)/(2)) in the first quadrant in such a way that its distance from the origin increases at the rate of 11 units/sec. The value of (dx)/(dt) when x = 3 is …………

A particle moves along the parabola y=x^(2) in the first quadrant in such a way that its x-coordinate (measured in metres) increases at a rate of 10 m/sec. If the angle of inclination theta of the line joining the particle to the origin change, when x = 3 m, at the rate of k rad/sec., then the value of k is

A particle moves along the parabola y=x^(2) in the first quadrant in such a way that its x-coordinate (measured in metres) increases at a rate of 10 m/sec. If the angle of inclination theta of the line joining the particle to the origin change, when x = 3 m, at the rate of k rad/sec., then the value of k is

The particle moves along the curve y=x^(2)+2x Then the point on the curve such that x and y coordiantes of the particle change with the same rate

A particle moves along the curve y=x^2+2x . Then the point on the curve such that x and y coordinates of the particle change with the same rate

A particle moves along the curve 12y=x^(3) . . Which coordinate changes at faster rate at x=10 ?

A particle moves along the curve 12y=x^(3) . . Which coordinate changes at faster rate at x=10 ?

A particle moves along the curve 12y=x^(3) . . Which coordinate changes at faster rate at x=10 ?

A particle moves along the curve x^(2)=2y . At what point, ordinate increases at the same rate as abscissa increases ?