Velocity of a particle varies with time as v=4t. Calculate the displacement of particle between `t=2` to t=4 sec.

(a) If s = 2t^(3)+ 3t^(2) + 2t + 8 then find time at which acceleration is zero. (b) Velocity of a particle (starting at t =0) varies with time as v= 4t. Calculate the displacement of part between t = 2 to t = 4 s

The accelerating of particle varies with time as shown (a)Find an expression for velocity in terms of t. (b)Calculate the displacement of the particle in the interval from t=2s "to" t4s .Assume that v=0 at t=0

The acceleration of particle varies with time as shown. (a) Find an expression for velocity in terms of t. (b) Calculate the displacement of the particle in the interval from t = 2 s to t = 4 s. Assume that v = 0 at t = 0.

The acceleration of particle varies with time as shown. (a) Find an expression for velocity in terms of t. (b) Calculate the displacement of the particle in the interval from t = 2 s to t = 4 s. Assume that v = 0 at t = 0.

If displacements of a particle varies with time t as s = 1/t^(2) , then.

A particle is moving with velocity v=4t^(3)+3 t^(2)-1 m//s . The displacement of particle in time t=1 s to t=2 s will be

Figure given here shows the variation of velocity of a particle with time. Find the following: (i) Displacement during the time intervals. (a) 0 to 2 sec., (b) 2 to 4 sec. and (c) 4 to 7 sec (ii) Accelerations at (a)t = 1 sec, (b) t = 3 sec. and (c)t = 6 sec. (iii) Average acceleration (a) between t = 0 to t = 4 sec. (b) between t = 0 to t = 7 sec. (iv) Average velocity during the motion.

The position of a particle varies with function of time as y=(4sin t+3cos t)m . Then the maximum displacement of the particle from origin will be