Wavelength of ligh used in an optical instrument are `lamda_`=4000A` and `lamda_2=5000A` , then ratio of their respective resolving powers (corresponding to `lamda_1` and `lamda_2`)

Wavelength of light used in an optical instrument are lambda_(1) = 4000 Å and lambda_(2) = 5000Å then ratio of their respective resolving powers (corresponding to lambda_(1) and lambda_(2) ) is

Wavelength of light used in an optical instrument are lambda_(1) = 4000 Å and lambda_(2) = 5000Å then ratio of their respective resolving powers (corresponding to lambda_(1) and lambda_(2) ) is

Wavelength of light used in an optical instrument are lambda_(1) = 4000 Å and lambda_(2) = 5000Å then ratio of their respective resolving resolving powers (corresponding to lambda_(1) and lambda_(2) ) is

Wavelength of light used in an optical instrument are lamda_(1)=4500 Å and lamda_(2)=6000 Å. What is the ratio of the resolving powers corresponding to lamda_(1) and lamda_(2) ?

Energy of a photon = E , kinetic energy of a proton is also the same as energy of the photon. Corresponding wavelength of the photon and de Broglie wavelength of the proton are lamda_(1) and lamda_(2) , respectively. What is the relation between E and the ratio of lamda_(1) and lamda_(2) ?

The ration of resolving powers of an optical microscope for two wavelangths lamda_(1) =4000 Å and lamda_(2)=6000 Å is

The ration of resolving powers of an optical microscope for two wavelangths lamda_(1) =4000 Å and lamda_(2)=6000 Å is