P(A cup B)=P(A cap B)` if and only if the relation between P(A) and P(B) is …………

P(A uu B) = P(A nn B) if and only if the relation between P(A) and P(B) is …………

If 'P(A cup B)'='P(A cap B)' for any two events A and B ,then

Assertion (A) : Let A and B be two events such that the occurrence of A implies occurrence of B, but not vice - versa, then the correct relation between P(A) and P (B) is P(B) ge P(A) Reason (R) : Here, according to the given statement A sube B P (B) = P (A cup (A cap B)) " " ( :' A cap B = A ) = P (A) + P (A cap B) Therefore, P (B) ge P (A)

P (A cup B) = 0.6, P(A cap B) = 0.2 Determine, P(A^c) + P(B^C) .

If P(A cup B)=0.8 and P(A cap B)=0.3 then the value of [P(barA)+P(barB)] is -

If A and B are events such that P(A' cup B') = (2)/(3) and P(A cup B) = (5)/(9) , then P(A') + P(B') = ……….

If A and B are such that P (A'cup B')=(2)/(3) and P (A cup B) = (5)/(9) , then P(A') + P(B') = ………….

Let A and B be two events such that P(A cup B)=P(A cap B) . Then, Statement-1: P(A cap overline(B))=P(overline(A) cap B)=0 Statement-2: P(A)+P(B)=1

Let A and B be two events such that P(A cup B)=P(A cap B) . Then, Statement-1: P(A cap overline(B))=P(overline(A) cap B)=0 Statement-2: P(A)+P(B)=1

If P(A cup B) = 0.8, P(A cap B) = 0.3, then P (bar(A)) + P (bar (B)) =