`f(x)=sqrt((x-2)sqrt(x-1))/(sqrt(x-1)-1). x` then `f'(10) & f'(3/2)=`

Let f(x)=(sqrt(x-2sqrt(x-1)))/(sqrt(x-1)-1).x then

Let f(x)=(sqrt(x-2sqrt(x-1)))/(sqrt(x-1)-1)*x then

Let f(x)=(sqrt(x-2 sqrt(x-1)))/(sqrt(x-1)-1) , then -

Let f(x)=(sqrt(x-2sqrt(x-1)))/(sqrt(x-1)-1)x .Then (a) f'(10)=1( b) f'((3)/(2))=-1( c)domain of f(x) is x>=1 (d)range of f(x)is(-2,-1)uu(2,oo)

Let f(x)=(sqrt(x-2(sqrt(x-1))))/(sqrt(x-1)-1)x then: (a) f'(10)=1( b) f'((3)/(2))=-1( c) domain of f(x) is x>=1( d) range of f(x) is (-2,-1)uu[2,oo]

"Let "f(x)=(sqrt(x-2sqrt(x-1)))/(sqrt(x-1-1))x." Then"

Let f(x)=(sqrt(x-2sqrt(x-1)))/(sqrt(x-1)-1).x then (a)domain of f(x) is x ge 1 (b)domain of f(x) is [1,infty)-{2} ?(c)f'(10)=1(d)f'(3/2)=-1

Let f(x) = (sqrt(x - 2 sqrt(x - 1)))/(sqrt(x - 1) - 1)x , then

if f(x)=sqrt(x+2sqrt(2x-4))+sqrt(x-2sqrt(2x-4)) then f'(3)+f'(6)= (A) 0 (B) 1 (C) 2 (D) 1/2

If f(x) = sqrt((sqrt(x-1)-2)^2)+sqrt((sqrt(x-1)-3)^2) , then f '(2) is equal to :