" or "int(2sin2 phi-cos phi)/(6-cos^(2)phi-4sin phi)d phi

int((3sin phi-2)cos phi)/(5-cos phi-4sin phi)d phi

Find int( (3 sin phi-2) cosphi)/(5-cos ^2 phi-4 sin phi) d phi

int((3sin phi-2)backslash cos phi)/(5-cos^(2)phi-4sin phi)backslash d phi

(3 cos phi+cos 3 phi)/(3 sin phi-sin 3 phi)=

Prove: (sin phi - cos phi) ^(2) =1 - sin 2 phi.

(1+sin phi+i cos phi)/((1+sin phi-i cos phi)^(n))=cos(n(pi)/(2)-n phi)+i sin(n(pi) /(2)-n phi)

If a sin phi+b cos phi=c then a cos phi-b sin phi is

If theta-phi=pi/2, prove that, [(cos^2 theta,cos theta sin theta),(cos theta sin theta,sin^2 theta)] [(cos^2 phi,cos phi sin phi),(cos phi sin phi,sin^2 phi)]=0