One ticket is selected at random from 100 tickets numbered `00,01,02, …, 99.` Suppose A and B are the sum and product of the digit found on the ticket, respectively. Then `P((A=7)//(B=0))` is given by

One ticket is selected at random from 100 tickets numbered 00, 01, 02, ….99. Suppose A and B are the sum and product of the digits found on the ticket. Then P(A=7|B=0) is given by

One ticket is selected at random from 100 tickets numbered 00, 01, 02,.., 99. Suppose A and B are the sum and product of the digit found on the ticket. Then P(A=7//B=0) is given by

One ticket is selected at random from 100 tickets numbered 00, 01, 02,.., 99. Suppose A and B are the sum and product of the digit found on the ticket. Then P(A=7//B=0) is given by

One ticket is selected at random from 100 tickets numbered 00, 01, 02,.., 99. Suppose A and B are the sum and product of the digit found on the ticket. Then P(A=7//B=0) is given by

One ticket is selected at random from 100 tickets numbered 00, 01, 02,.., 99. Suppose A and B are the sum and product of the digit found on the ticket. Then P(A=7//B=0) is given by

One ticket is selected at random from 100 tickets numbered 00,01,02,...,98,99. Suppose S and T are the sum and product of the digits of the number on the ticket, then the probability of getting S=9 and T=0 is 2//19 b. 19//100 c. 1//50 d. none of these

One ticket is selected at random from 100 tickets numbered 00,01,02,...,98,99. If x_1, a n dx_2 denotes the sum and product of the digits on the tickets, then P(x_1=9//x_2=0) is equal to

One ticket is selected at random from 100 tickets numbered 00,01,02,...,98,99. If x_(1), and x_(2) denotes the sum and product of the digits on the tickets,then P(x_(1)=9/x_(2)=0) is equal to 2/19 b.19/100 c.1/50 d.none of these