2^(2^(2))-:((2^(2))^(2))^(2)=?

The value of Delta = |(1^(2),2^(2),3^(2)),(2^(2),3^(2),4^(2)),(3^(2),4^(2),5^(2))| is

The value of Delta = |(1^(2),2^(2),3^(2)),(2^(2),3^(2),4^(2)),(3^(2),4^(2),5^(2))| , is

1^(2)+(1^(2)+2^(2))+(1^(2)+2^(2)+3^(2))+......n brackets =

Using the given pattern,find the missing numbers: 1^(2)+2^(2)+2^(2)=3^(2)2^(2)+3^(2)+6^(2)=7^(2)3^(2)+4^(2)+12^(2)=13^(2)4^(2)+5^(2)+()^(2)=21^(2)5^(2)+()^(2)+30^(2)=31^(2)6^(2)+7^(2)+()^(2)=()^(2)

If A=[[1^(2),2^(2),3^(2)2^(2),3^(2),4^(2)3^(2),4^(2),5^(2)]] then |Adj A|=

If A=[[1^(2),2^(2),3^(2)2^(2),3^(2),4^(2)3^(2),4^(2),5^(2)]] then |AdjA|=

Find the nth terms and the sum to n term of the series : 1^(2)+(1^(2)+2^(2))+(1^(2)+2^(2)+3^(2))+...

Find the sum to n terms of the series 1^(2)+(1^(2)+2^(2))+(1^(2)+2^(2)+3^(2))+.....

Find the sum to n terms of the series : 1^(2)+(1^(2)+2^(2))+(1^(2)+2^(2)+3^(2))+ ….