(2^(2^(2)))/(((2^(2))^(2))^(2))=?

If =cos^(2)[tan^(-1)(sin cot^(-1)x)], then (dy)/(dx) is (-2x)/((x^(2)+2)^(2))(b)(2x)/((x^(2)+2)^(2))(2)/((x^(2)+2)^(2)) (d) (-2)/((x^(2)+2)^(2))

1^(2)+(1^(2)+2^(2))+(1^(2)+2^(2)+3^(2))+......n brackets =

(1^(2).2^(2))/(1!)+(2^(2).3^(2))/(2!)+(3^(2).4^(2))/(3!)+....=

Using the given pattern,find the missing numbers: 1^(2)+2^(2)+2^(2)=3^(2)2^(2)+3^(2)+6^(2)=7^(2)3^(2)+4^(2)+12^(2)=13^(2)4^(2)+5^(2)+()^(2)=21^(2)5^(2)+()^(2)+30^(2)=31^(2)6^(2)+7^(2)+()^(2)=()^(2)

The value of Delta = |(1^(2),2^(2),3^(2)),(2^(2),3^(2),4^(2)),(3^(2),4^(2),5^(2))| is

The value of Delta = |(1^(2),2^(2),3^(2)),(2^(2),3^(2),4^(2)),(3^(2),4^(2),5^(2))| , is

Find the nth terms and the sum to n term of the series : 1^(2)+(1^(2)+2^(2))+(1^(2)+2^(2)+3^(2))+...

Sum of series 1^(2)+(1^(2)+2^(2))+(1^(2)+2^(2)+3^(2))+... upto 22 terms is

Find the sum to n terms of the series : 1^(2)+(1^(2)+2^(2))+(1^(2)+2^(2)+3^(2))+ ….