[" 1./ The period of sin "^(2)theta" is "],[[" (a) "pi^(2)," (b)."pi," (c) "2 pi]]

The period of sin^2theta is

The period of sin (pi sin theta) is

The period of sin(pi sin theta) is

Period of sin theta - sqrt2 cos theta is

The period of the function f( theta ) = sin""(theta )/(3) + cos""(theta )/(2) is

If u = (1 + cos theta) (1+ cos2 theta) - sin theta sin 2theta, v = sin theta (1 + cos2 theta) + sin 2 theta(1 + cos theta), "show that" u^(2) + v^(2) = 4(1 + cos theta) (1 + cos 2theta).

(1)/(sin^(2)theta)-(cos^(2)theta)/(sin^(2) theta) =___.