Two particles A and B having charges of `+2.00 xx 10^(-6) C` and of `- 4.00xx 10^(-6)` respectively are held fixed at a separation of 20.0 cm . Locate the point(s) on the line AB where (a) the electric field is zero (b) the electric potential is zero.

Explanation

To solve the problem, we need to find the points along the line connecting two charges A and B where the electric field and electric potential are zero.

### Given:
- Charge A, \( Q_A = +2.00 \times 10^{-6} \, C \)
- Charge B, \( Q_B = -4.00 \times 10^{-6} \, C \)
- Separation distance between A and B, \( d = 20.0 \, cm = 0.20 \, m \)

### Part (a): Locate the point where the electric field is zero.
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