A water particle of mass 10.0 mg and having a charge of `1.50 xx 10^(-6)C` stays suspended in a room. What is the magnitude of electric field in the room ? What is its direction?

Options

A. `66.7 N//C` in downward direction
B. `66.7 N//C` in upward direction
C. `6.7 N//C` in upward direction
D. `6.7 N//C` in downward direction

Answer

B

Explanation

`m=10mg=10xx10^-2xx10^-3kg `
` Q=1.5xx10^-6C `
` But QE =mg `
` rArr E=(mg)/Q =(10xx10^-5xx10)/1.5xx10^-6 `
` 1000/15=66.7 N//C `
Its direction will be upward .