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A 10 cm long rod carries a charge of +15...

A 10 cm long rod carries a charge of `+150 muC` distributed uniformly along its length. Find the magnitude of the electric field at a point 10 cm from both the ends of the rod.

A

`15.6 xx 10^7 N//C`

B

`15.6 xx 10^5 N//C`

C

`1.56 xx 10^7 N//C`

D

`1.56 xx 10^5 N//C`

Text Solution

Verified by Experts

The correct Answer is:
A

`Net electric field =intdEcos theta `
`int1/(4piepsilon_0)(q/ldx)/((x^2+125)).x/(sqrt(x^2+125)) `
` int_(-10)^(10)1/(4piepsilon_0).q/l(xdx)/(sqrt(x^2+125)).(x^2+125) `
` 5.2xx10^7N//C`.
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