Some equipotential surfaces are shown in figure(29.E3) What can you say about the magnitude and the direction of the electric field?

Explanation

` (a) The angle between potential edl=dv change in potential =10V=dV `
` As E=rdV `
` (As potential surface) `
` S0, Edl=dv `
` rArr Edlcos(90+30) =-dV `
` rArr E(10xx10^-2)cos120=-dV `
` E=200V//m `
making an angle 120 with yaxis
(b) As electric field intensity is r to potential surface
` So, E=r `
` rArr =60vq `
` So, E=v.m=V.M. `