Two particles, carrying charges -q and +q and having equal masses m each, are fixed at the rod is clamped at an end and is placed in a uniform electric field E with the axis of the dipole along the electric field. The rod is slightly tlted and then released. Neglecting gravity find the time period of small oscillations.

Explanation

Consider the rod to be a simple pendulum
For simple pendulum
` T=2pisqrt(l/g) `
` (l=length,g=accln) `
Now force experienced by the charges
` F=Eq `
Now, `accln =F/m=(Eq)/m `
Here,`length =a `
So, time periode
` T=2pisqrt((ma)/(qE))`