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A uniform electric field of magnitude E=...

A uniform electric field of magnitude `E= 100 N C^(-1)` exists in the space in x-direction. Calculate the flux of this field through a plane square of edga 10 cm placed in the y-z plane. Take the normal along the positive x-axis to be positive.

Text Solution

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The Flux `Phi = int E cos theta dS`. As the normal to the area point along the electric field, `theta = 0` . Also, `E` is unifrom, so
`Phi = E Delta S`
`=(100 NC^(-1)) (0.10m)^(2) = 1.0 Nm^(2)C^(-1)`.
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Knowledge Check

  • A uniform electric field E=2xx10^(3)NC^(-1) is acting along the positive x-axis. The flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane is

    A
    `20NC^(-1)m^(2)`
    B
    `30NC^(-1)m^(2)`
    C
    `10NC^(-1)m^(2)`
    D
    `40NC^(-1)m^(2)`
  • Consider a uniform electric field E = 3 xx 10^(3) hat(i)N C^(-1) . What is te flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane ?

    A
    `10 N C^(-1) m^(2)`
    B
    `20 N C^(-1) m^(2)`
    C
    `30 N C^(-1) m^(2)`
    D
    `40 N C^(-1) m^(2)`
  • There exists an electric field of 1 NC^(-1) along Y direction. The flux passing through the square of 1 m placed in xy- plane inside the electric field is

    A
    `1.0 Nm^(2)C^(-1)`
    B
    `10.0 Nm^(2)C^(-1)`
    C
    `2.0 Nm^(2)C^(-1)`
    D
    zero
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