The electric field in a region is given by `vecE=E_0x/iota veci`. Find the charge contained inside a cubical volume bounded by the curfaced `x=0, x=alpha, y=0, y=alpha, z=0 and z= alpha`. Take `E_0= 5 xx 10^3 N C^(-1)`, `iota= 2cm and alpha=1 cm`.

Explanation

To find the charge contained inside the cubical volume bounded by the surfaces \( x=0, x=\alpha, y=0, y=\alpha, z=0, z=\alpha \) given the electric field \( \vec{E} = \frac{E_0 x}{\iota} \hat{i} \), we will use Gauss's Law, which states:

\[ \oint \vec{E} \cdot d\vec{A} = \frac{Q_{\text{enc}}}{\epsilon_0} \]

### Step 1: Identify the surfaces of the cube
The cube is bounded by the following surfaces:
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