As `C=(1/V)Q`, can you say that the capacitor `C` is proportion to the charge `Q`?

As we know in steady state charge on a capacitor is given as Q= CV which also implies C= Q//V . So can we say in steady state capacitance is proportional to the supplied charge Q .

Consider the situation shown in (figure) what are the signs of q_1 and q_2 ? If the lines are drawn in proportion to the charge, what is the ratio q_1/q_2 ?

In the given circuit C_1 = C, C_2 = 2C, C_3 = 3C . If charge at the capacitor C_2 is Q. Then the charge at the capacitor C_3 will be

Two capacitors of equal capacitance ( C_1 = C_2 ) are shown in the figure. Initially, while the switch S is open, one of the capacitors is uncharged and the other carries charge Q0. The energy stored in the charged capacitor is U0. Sometimes after the switch is colsed, the capacitors C_1 and C_2 carry charges Q_1 and Q_2, respectively, the voltages across the capacitors are V_1 and V_2 , and the energies stored in the capacitors are U_1 and U_2 . Which of the following statements is INCORRECT ?