A charge of 20 muC is placed on the positive plante of on isolated parailel - plate capacitor of capacitance `10 muF` calculate the potential difference developed between the plates .

Explanation

To solve the problem, we need to calculate the potential difference developed between the plates of a parallel plate capacitor when a charge is placed on one of the plates. Here's a step-by-step solution:

### Step 1: Understand the Given Values
We are given:
- Charge (Q) = 20 µC = 20 × 10^(-6) C
- Capacitance (C) = 10 µF = 10 × 10^(-6) F

### Step 2: Recall the Formula for Potential Difference
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