Calculate the electric field in a copper wire of cross-sectional area`2.0mm^(2)` carrying a current of 1A .The resistivity of copper `=1.7xx10^(-8)(Omega)m`.

Explanation

` A = 2 xx (10^-6)(m^2), i= 1A,`
rho = (1.7 xx (10^-8)Omega-m, E = ?`)
` R = rhol/A = (1.7 xx (10^-8)xx l/2 xx (10^-6))`
` V = iR = (1.7 xx (10^-8) xx l/2 xx (10^-6))`
` E = dV/dL = V/t`
` = (1.7 xx (10^-8) xx l/2 xx (10^-6))`
` = 17/2 xx (10^-3) V/m = 8.5 mV/m.`