Find the current through the `10(Omega)`resistor shown in figure.

Explanation

In the circuit ABCDA,
3i+ 6i_1 -4.5 = 0 `
In the circuit GEFCG,
` (i-i_1) 10+ 3 -6i_1 = 0 `
` 3i + 6i_1 = 4.5 `
` 10i - 16i_1 = -3 `
` rArr [10i + 16i_1 = 3] 3 `
` [3i+6i_1 = 4.5]10 `
` 30i - 48i_1 = -9 `
` 30i - 60i_1 = 45`
` -108i= -54 `
` i_1 = 54/108 = 1/2 = 0.5.`
`3i + 6 xx 1/2 -4.5 = 0 `
` 3i - 1.5 = 0 `
` rArr i= 1.5/3 = 0.5 `
Current through 10m register = 0A.