Find the charge on the capacitor shown in figure

Explanation

In steady state condition, no current flows
through the capacitors
` R_eff = 10+20 = 30Omega `
` i= 2/30 = 1/15 A .`
` Voltage drop across 10m resister = ixx r `
` = 1/15 xx 10 `
` = 10/15 = 2/3 V. `
` Charge stored on the capacitor(Q) = CV `
` = 6 xx (10^-6) xx 2/3 `
` = 4 xx (10^-6)C = 4 mC. `