A capacitor of capacitance as C is given a charge Q. At `t=0`,it is connected to an ideal battery of emf `(epsilon)`through a resistance R. Find the charge on the capacitor at time t.

Explanation

The capacitor is given a charge Q. It will
discharge and the capacitor will be
charged up when connected with battery
Net charge at time .
`t = Q e^(-t/RC) + q{ 1-e^(-t/RC)}`
` t= Q e^(-t/RC) + C epsilon { 1 - e^(-t/RC)}`.