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Calculate the electric current required to deposit `0.972 g` of chromium in three hours. ECE of chromium is `0.00018 g C^(-1)`

Text Solution

Verified by Experts

We have
`m=Zit`
or `0.972 g = (0.00018 g C^(-1) I ( 3 xx 3600 s)`
or, `(0.972)/(0.00018 xx 3 xx 3600) A = 0.50A`
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